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MYSQL Issues


Alexandru Solomon

Question

Salut,

de curand am inceput un "sistem" de vara.

Cu o comanda ce-ti permite un bonus.

"summerbonus"

Oricum, ceea ce nu inteleg, este ca:

1. Am un tabel in 'users' numit 'SummerBonus' in care daca ai valoarea 1, nu mai poti folosi comanda.

2. Nu am gasit niciun tutorial explicativ cum sa folosesti mysql.

Comanda mea arata pana cum asa:

https://pastebin.com/Lis1tyNM

 

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Acum 2 ore, Alexandru Solomon a spus:

Salut,

de curand am inceput un "sistem" de vara.

Cu o comanda ce-ti permite un bonus.

"summerbonus"

Oricum, ceea ce nu inteleg, este ca:

1. Am un tabel in 'users' numit 'SummerBonus' in care daca ai valoarea 1, nu mai poti folosi comanda.

2. Nu am gasit niciun tutorial explicativ cum sa folosesti mysql.

Comanda mea arata pana cum asa:

https://pastebin.com/Lis1tyNM

 

  • format(string,sizeof(string),"UPDATE `users` SET `SummerBonus` = '1 WHERE `name` = '%s'",PlayerName);
  • mysql_query(string);
if(PlayerInfo[playerid][pSummerBonus] == 1) return SCM(playerid, -1, "Acest bonus poate fii folosit o singura data!"); // aici verifica daca summerbonus este = cu 1. Probabil ca sa interzici vrei sa pui 0. Asa ca pur si simplu inlocuiesti treaba. Pui 0 in loc de 1.
Si in comanda adauga la final:
PlayerInfo[playerid][pSummerBonus] = 0;
Edited by BaFFyJunior
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On 2/18/2020 at 5:11 PM, BaFFyJunior said:
  • format(string,sizeof(string),"UPDATE `users` SET `SummerBonus` = '1 WHERE `name` = '%s'",PlayerName);
  • mysql_query(string);
if(PlayerInfo[playerid][pSummerBonus] == 1) return SCM(playerid, -1, "Acest bonus poate fii folosit o singura data!"); // aici verifica daca summerbonus este = cu 1. Probabil ca sa interzici vrei sa pui 0. Asa ca pur si simplu inlocuiesti treaba. Pui 0 in loc de 1.
Si in comanda adauga la final:
PlayerInfo[playerid][pSummerBonus] = 0;

la compilare imi apare eroarea error 035: argument type mismatch (argument 1)

pe linia 

            format(string,sizeof(string),"UPDATE `users` SET `SummerBonus` = '1 WHERE `name` = '%s'",PlayerName);
            mysql_query(string);    <- aici apare eroarea

https://imgur.com/WtOFL40

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