Nu imi apare un dialog

[ScaRLighT]

Problema intalnita (descriere): Dupa ce ma inregistrez ar trebuie sa-mi mai apara dialogul in care iti alegi sexul, dar nu apare si imi muta camera (vezi imaginea).
Ero(area / rile) / warning-(ul / urile): Nu am
Liniile de cod / sursa / script-ul(obligatoriu):

function OnPlayerRegister(playerid)
{
    new string[128], hours, minutes, year, month, day, loginstring[128];
	PlayerData[playerid][ID] = cache_insert_id();
	
	gettime(hours, minutes);
	getdate(year, month, day);
	
	format(string, sizeof(string), "%02d.%02d.%02d %02d:%02d",day,month,year,hours,minutes);
	strmid(PlayerData[playerid][RegDate], string, 0, strlen(string), 255);

	mysql_format(SQL, string,128,"UPDATE `users` SET `RegisterDate`='%s' WHERE `Name`='%s' LIMIT 1",PlayerData[playerid][RegDate],PlayerData[playerid][Name]);
	mysql_tquery(SQL, string, "", "");
	
 //despre acest dialog este vorba
	ShowPlayerDialog(playerid, DIALOG_GENDER, DIALOG_STYLE_LIST, "Please choose your gender", "Male\nFemale", "Select", "Cancel");
	
	ServerInfo[users]++;
	strmid(ServerInfo[newestacc], PlayerData[playerid][Name], 0, strlen(PlayerData[playerid][Name]), 255);

	mysql_format(SQL, loginstring,128,"UPDATE `infos` SET `users`='%d' WHERE ID = 1",ServerInfo[users]);
	mysql_tquery(SQL, loginstring, "", "");
	mysql_format(SQL, loginstring,128,"UPDATE `infos` SET `newestacc`='%s' WHERE ID = 1",ServerInfo[newestacc]);
	mysql_tquery(SQL, loginstring, "", "");
	
	return 1;
}

Iar acesta este codul dialogului:

case DIALOG_GENDER:
		{
		    if(response)
			{
			    if(listitem == 0)
				{
				    PlayerData[playerid][Character] = 250;
					PlayerData[playerid][Gender] = 1;
                    Update(playerid, CharacterUpdate);
					Update(playerid, GenderUpdate);

			//Apoi ar trebui sa treaca la acesta.			
                    format(string, sizeof(string), "Account registered, you can login now by typing your password below.");
	                ShowPlayerDialog(playerid, DIALOG_LOGIN, DIALOG_STYLE_PASSWORD, "Login", string, "Login", "Abort");
					return 0;
			    }
				if(listitem == 1)
				{
				    PlayerData[playerid][Character] = 56;
					PlayerData[playerid][Gender] = 2;
                    Update(playerid, CharacterUpdate);
					Update(playerid, GenderUpdate);

					format(string, sizeof(string), "Account registered, you can login now by typing your password below.");
	                ShowPlayerDialog(playerid, DIALOG_LOGIN, DIALOG_STYLE_PASSWORD, "Login", string, "Login", "Abort");
					return 0;
				}
			}
			else Kick(playerid);
		}

Imagini / Video (optional): http://imgur.com/m4obQUQ
Ati incercat sa rezolvati singur?: Da, am incercat.

Edited August 20, 2016 by ScaRLighT

[kwnx]

Te rog sa postezi si functia in care accesezi OnPlayerRegister, din cate vad pare sa fie un query.

[ScaRLighT]

	    case DIALOG_REGISTER:
	    {
	        if(!response)
	            return Kick(playerid);

			if((strlen(inputtext) > 0) && (strlen(inputtext) < 25))
		    {
			    new ip[25];
			    GetPlayerIp(playerid, ip, sizeof(ip));
				WP_Hash(PlayerData[playerid][Password], 129, inputtext);

				mysql_format(SQL, query, sizeof(query), "INSERT INTO `users` (`Name`, `Password`, `IP`) VALUES ('%e', '%s', '%e')", PlayerData[playerid][Name], PlayerData[playerid][Password],ip);
				mysql_tquery(SQL, query, "OnPlayerRegister", "d", playerid);
			}
			else
			{
				SendClientMessage(playerid, COLOR_WHITE, "{FF0000}AdmBot{FFFFFF}: You've enter a very long password, nice try. Your IP was saved in our log.");
			/*	format(string, sizeof(string), "%s enters a very long password in login dialog",PlayerData[playerid][Name]);
				FloodLog(string,playersip); */
				format(string, 256, "Warning: %s(%d) enters a very long password in login dialog | IP: %s", PlayerData[playerid][Name],playerid,playersip);
				ABroadCast(RED,string,1);
				KickEx(playerid);
			}
	    }

EDIT: Am rezolvat problema. Era din cauza unor tabele din MySQL care nu aveau default value. Erorile mi-au aparut ulterior.

Edited August 21, 2016 by ScaRLighT
Problem solved!